Q. The current in a conductor varies with time $t$ as $I = 2t + 3t^{2}$ where $I$ is in $ampere$ and $t$ in $seconds.$ Electric charge flowing through a section of the conductor during $t = 2\ sec$ to $t = 3\ sec$ is

A) $10\ C$
B) $24\ C$
C) $33\ C$
D) $44\ C$
Explanation

(b) $dQ = Idt \Rightarrow Q = \int_{t = 2}^{t = 3}{Idt = \left\lbrack 2\int_{2}^{3}{tdt + 3\int_{2}^{3}{t^{2}dt}} \right\rbrack}$
$= \left\lbrack t^{2} \right\rbrack_{2}^{3} + \left\lbrack t^{3} \right\rbrack_{2}^{3} = (9 - 4) + (27 - 8) = 5 + 19 = 24C$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.