(b) The amount of chlorine
$m = zlt = z\left( \frac{P}{V} \right)\ t\ \ \ \ \ \ \ \ \ \ \ \ \ \lbrack\because P = VI\rbrack$
$\ \ \ \ \ = 0.367 \times 10^{- 6} \times \left( \frac{100 \times 1000}{125} \right) \times 60$
$\ \ \ \ = 0.017616\ kg = 17.616\ g$