(a) Given current $I = 2A$
(i) If current is in clockwise direction then from Kirchhoff’s second law
$6 \times 2 + 20 - E = 0$
$\Longrightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E = 32V$
(ii) If the current is in anticlockwise direction, then
$6 \times 2 + E - 20 = 0$
$\Longrightarrow \ \ \ E - 8 = 0$
E=8