Q. Two resistors of $6\ \Omega$ and $9\Omega$ are connected in series to a $120\ volt$ source. The power consumed by the $6\ \Omega$ resistor is
A) $384\ W$
B) $576\ W$
C) $1500\ W$
D) $1200\ W$
Explanation
(a) $Current\ through\ the\ combination\ i = \frac{120}{(6 + 9)} = 8\ A$
So, power consumed by $6\ \Omega$ resistance
$P = (8)^{2} \times 6 = 384\ W$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.