Q. Temperature of cold junction in a thermocouple is $270℃,$ then the temperature of inversion is
A) $540℃$
B) $530℃$
C) $280℃$
D) $260℃$
Explanation
(b) Temperature of inversion is
$T_{i} = 2T_{n} - T_{0}$
$\therefore T_{i} = 2 \times 270 - 10 = 530℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.