Q. Two resistance $R_{1}$ and $R_{2}$ are joined as shown in the figure to two batteries of e.m.f. $E_{1}$ and $E_{2}.$ If $E_{2}$ is short-circuited, the current through $R_{1}$ is
A) $E_{1}/R_{1}$
B) $E_{2}/R_{1}$
C) $E_{2}/R_{2}$
D) $E_{1}/(R_{2} + R_{1})$
Explanation
(a) After short circuiting, $R_{2}$ becomes meaningless
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.