Q. A steady current of 1.5 A flows through a copper voltameter for 10 min. If the electrochemical equivalent of copper is $30 \times 10^{- 5}\ g\ C^{- 1},$ the mass of copper deposited on the electrode will be
A) 0.40 g
B) 0.50 g
C) 0.67 g
D) 0.27 g
Explanation
(d) According to Faraday’s law of electrolysis
$m = zit$
Here, $i = 1.5\ A,\ t = 10\ min = 10 \times 60\ s$
$\ \ \ \ \ \ \ \ \ \ \ \ z = 30 \times 10^{- 5}\ {gC}^{- 1}$
Hence, mass of copper deposited on the electrode
$m = 30 \times 10^{- 5} \times 1.5 \times 10 \times 60 = 27 \times 10^{- 2} = 0.27\ g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.