Q. A 2V battery, a 990$\ \Omega\ $resistor and a potentiometer of 2m length, all are connected in series of the residence of potentiometer wire is 10$\ \Omega,$ then the potential gradient of the potentiometer wire is
A) 0.05$Vm^{- 1}$
B) 0.5$Vm^{- 1}$
C) 0.01$Vm^{- 1}$
D) $0.1\ Vm^{- 1}$
Explanation
(c) Potential gradient
$x = \frac{e}{\left( R + R_{h} + r \right)}.\frac{R}{L}$
$\Longrightarrow \ \ x = \frac{2}{(990 + 10)} \times \frac{10}{2}$
$= 0.01\ Vm^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.