Q. Resistances of $6\ ohm$ each are connected in the manner shown in adjoining figure. With the current $0.5\ ampere$ as shown in figure, the potential difference $V_{P} - V_{Q}$ is
A) $3.6\ V$
B) $6.0\ V$
C) $3.0\ V$
D) $7.2\ V$
Explanation
(c) $V_{p} - V_{q} = \left( \frac{6}{3} + \frac{12 \times 6}{12 + 6} \right)(0.5) = (2 + 4)(0.5) = 3V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.