Q. If a steady current of 100 A is passed then how much time is taken to deposit 0.254 kg of copper on the cathode of copper voltmeter. Use the known value of Faraday constant and relative atomic mass of copper is 63.5.
A) 15440 s
B) 7720 s
C) 3760 s
D) 5480 s
Explanation
(b) $m = \ z = \frac{E}{F}It = \frac{(M/P)}{F}It$
or$\ t\ = \frac{mF_{P}}{MI} = \frac{(0.254 \times 10^{3}) \times 96500 \times 2}{63.5 \times 100}$
$= 7720\ $s.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.