Q. A $12\ V$ lead accumulator is being charged using $24\ V$ supply with an external resistance $2\Omega.$ The internal resistance of the accumulator is $1\Omega.$ Find the time in which it will store $360\ W$-hour energy
A) $1\ hr$
B) $7.5\ hr$
C) $10\ hr$
D) None of these
Explanation
(b) $i = \frac{24 - 12}{3} = 4\ A,\ $Time of charging$\ t = \frac{360}{V.i}$
$\Rightarrow t = \frac{360}{12 \times 4} = 7.5\ hours$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.