Q. The circuit shown here is used to compare the e.m.f.'s of two cells $E_{1}$ and $E_{2}\left( E_{1} > E_{2} \right).$ The null point is at $C$ when the galvanometer is connected to $E_{1}.$ When the galvanometer is connected to $E_{2},$ the null point will be
A) To the left of $C$
B) To the right of $C$
C) At $C$ itself
D) No where on $AB$
Explanation
(a) $E \propto l$ (balancing length)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.