Q. The range of a voltmeter of resistance 500$\ \Omega$ is 10V. the resistance to be connected to convert it into an ammeter of range 10A is
A) 1$\ \Omega$ in parallel
B) 1$\ \Omega$ in series
C) 0.1$\ \Omega$ in parallel
D) 0.1$\ \Omega$ in series
Explanation
(c) Here, $V\ = 10V,\ G = 500\Omega$
$i_{g} = \frac{V}{G} = \frac{10}{500} = 2 \times 10^{- 2}A$
Now,
$S = \frac{i_{g}G}{i - i_{g}} = \frac{2 \times 10^{- 2} \times 500}{10 - 2 \times 10^{- 2}} \simeq 1\Omega\ in\ parallel.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.