Q. In the figure shown, the total resistance between $A$ and $B$ is
A) $12\ \Omega$
B) $4\ \Omega$
C) $6\ \Omega$
D) $8\ \Omega$
Explanation
(d) The last two resistances are out of circuit. Now $8\Omega$ is in parallel with $(1 + 1 + 4 + 1 + 1)\Omega$
$\therefore R = 8\Omega||8\Omega = \frac{8}{2} = 4\Omega \Rightarrow R_{AB} = 4 + 2 + 2 = 8\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.