(a) $R = \frac{Sl}{A} = \frac{Sl^{2}}{V}$ $\therefore\ \ \ \frac{\mathrm{\Delta}R}{R} = 2\frac{\mathrm{\Delta}l}{l} = + 2.0\%$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.