Q. In the circuit shown in the figure, the current through
A) The $3\Omega$ resistor is $0.50\ A$
B) The $3\Omega$ resistor is $0.25\ A$
C) The $4\Omega$ resistor is $0.50\ A$
D) The $4\Omega$ resistor is $0.25\ A$
Explanation
(d) Equivalent resistance of the circuit $R = 9\Omega$
$\therefore$ Main current $i = \frac{V}{R} = \frac{9}{9} = 1A$
After proper distribution, the current through $4\Omega$ resistance is $0.25\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.