Q. As the switch $S$ is closed in the circuit shown in figure, current passed through it is
A) Zero
B) 1 A
C) 2 A
D) 1.6 A
Explanation
(c) Let $V$ be the potential at $C$
Using Kirchhoff’s first law $i_{1} + i_{2} = i_{3}$
$\frac{10 - V}{4} + \frac{5 - V}{2} = \frac{V - 0}{2}$
On solving, $V = 4\ $Volt, $i_{3} = \frac{V}{2} = \frac{4}{2} = 2A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.