Q.
Find the power of the circuit
A) $1.5\ W$
B) $2\ W$
C) $1\ W$
D) None of these
Explanation
(c) In steady state the branch containing capacitors, can be neglected. So reduced circuit is as follows
[image:3_image163.emf]
Power$\ P = \frac{V^{2}}{R} = \frac{(2)^{2}}{4} = 1W$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.