Q. Amount of electricity required to pass through the $H_{2}O$ voltmeter so as to liberate $11.2\ litre$ of hydrogen will be
A) $1\ faraday$
B) $\frac{1}{2}faraday$
C) $2\ faraday$
D) $3\ faraday$
Explanation
(a) $22.4\ litre\ H_{2} = 1\ $mole of$\ H_{2} = N$ molecules of $H_{2}$
$= 2N$ atoms of $H$
So charge required to liberate $22.4\ litre$ of $H_{2} = 2Ne = 2F$
Hence charge required to liberate $11.2\ litre$ of $H_{2} = F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.