Q. 2, 4 and 6 $S$ are the conductance of three conductors. When they are joined in parallel, their equivalent conductance will be
A) $12\ S$
B) $(1/12)S$
C) $(12/11)S$
D) $(11/12)S$
Explanation
(a) $R_{1} - \frac{1}{2\Omega},R_{2} = \frac{1}{4\Omega};R_{3} = 1/6\Omega$
In parallel; $\frac{1}{R_{p}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R3\ } = 2 + 4 + 6 = 12$
or Equivalent conductance, $G = \frac{1}{R_{p}} = 12S$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.