Q. The current flowing in a coil of resistance $90\ \Omega$ is to be reduced by 90%. What value of resistance should be connected in parallel with it
A) $9\ \Omega$
B) $90\ \Omega$
C) $1000\ \Omega$
D) $10\ \Omega$
Explanation
(d) $i_{g} = \frac{i}{10} \Rightarrow$ Required shunt $S = \frac{G}{(n - 1)} = \frac{90}{(10 - 1)} = 10\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.