Q. Six equal resistances each of $4\Omega$ are connected to form a figure. The resistance between two corners $A$ and $B$ is
A) $4\ \Omega$
B) $4/3\ \Omega$
C) $12\ \Omega$
D) $2\ \Omega$
Explanation
(b) Equivalent circuit of this combination of resistances is as shown in figure. The effective resistance of arm
$EG = \frac{4 \times 4}{4 + 4} = 2\Omega$
Total resistances between $A$ and $B$ will be
$\frac{1}{R} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4} = \frac{3}{4}\ or\ R = \frac{4}{3}\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.