Q.
In the circuit shown as $P \neq R$ and the reading of the galvanometer $G$ is same with switch open or closed. Then
A) $I_{R} = R_{G}$
B) $I_{P} = I_{G}$
C) $I_{Q} = I_{G}$
D) $I_{Q} = I_{R}$
Explanation
(a) As galvanometer deflection remains unaffected with switch $S$ open or closed, hence the bridge circuit is balanced. Hence, $I_{p} = I_{Q}$and $I_{R} = I_{G}$
However, as $P \neq R$, hence $I_{P} \neq I_{R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.