Q. In the given circuit, the potential of the point $E$ is
A) Zero
B) $- 8\ V$
C) $- 4/3\ V$
D) $4/3\ V$
Explanation
(c) The current in the circuit $= \frac{8}{5 + 1} = \frac{4}{3}$
Now $V_{C} - V_{E} = \frac{4}{3} \times 1 \Rightarrow V_{E} = - \frac{4}{3}V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.