Q. A potential divider is used to give outputs of $4\ V$ and $8\ V$ from a $12\ V$ source. Which combination of resistances, $(R_{1}:R_{2}:R_{3})$ gives the correct voltages?

A) 2 : 1 : 2
B) 1 : 1 : 1
C) 2 : 2 : 1
D) 1 : 1 : 2
Explanation

(b) Resistors are connected in series. So current through each resistor will be same
$\Rightarrow i = \frac{12 - 8}{R_{3}} = \frac{8 - 4}{R_{2}} = \frac{4 - 0}{R_{1}} \Rightarrow \frac{4}{R_{3}} = \frac{4}{R_{2}} = \frac{4}{R_{1}}$
So, $R_{1}:R_{2}:R_{3} :: 1:1:1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.