(b) Resistors are connected in series. So current through each resistor will be same
$\Rightarrow i = \frac{12 - 8}{R_{3}} = \frac{8 - 4}{R_{2}} = \frac{4 - 0}{R_{1}} \Rightarrow \frac{4}{R_{3}} = \frac{4}{R_{2}} = \frac{4}{R_{1}}$
So, $R_{1}:R_{2}:R_{3} :: 1:1:1$