Q. Four resistances are connected in a circuit in the given figure. The electric current flowing through $4\ ohm$ and $6\ ohm$ resistance is respectively
A) $2\ amp$ and $4\ amp$
B) $1\ amp$ and $2\ amp$
C) $1\ amp$ and $1\ amp$
D) $2\ amp$ and $2\ amp$
Explanation
(d) Equivalent resistance $= \frac{4 \times 4}{4 + 4} + \frac{6 \times 6}{6 + 6} = 5ohm$ So the current in the circuit $= \frac{20}{5} = 4\ ampere$ Hence the current flowing through each resistance $= 2\ ampere$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.