(b) Electric power consumed by kettle $P = 220 \times 4W$
Heat required
$H = 1000 \times 1(100 - 20) = 1000 \times 80\ cal = 4200 \times 80\ J$
$P = \frac{H}{t} \Rightarrow H = P \times t$
$\therefore 220 \times 4 \times t = 4200 \times 80 \Rightarrow t = 6.3\ minutes$