Q. A galvanometer has a resistance of 3663$\Omega$. A shunt S is connected across it such that (1/34) of the total current passes through the galvanometer. Then the value of shunt is
A) 3663$\Omega$
B) 111$\Omega$
C) 107.7$\Omega$
D) 3555.3$\Omega$
Explanation
(b) Shunt
$S = \frac{I_{g}G}{I - I_{g}}$
Here, $\frac{I_{g}}{I} = \frac{1}{34}$
$\therefore\frac{1}{34} = \frac{S}{S + G}\ $
$\therefore\ \ S = \frac{G}{33} = \frac{3663}{33} = 111\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.