Q. The value of current required to deposit $0.972\ gm$ of chromium in $3\ hours$ if the E.C.E. of chromium is 0.00018 $gm$ per coulomb, is
A) $1\ amp$
B) $1.5\ amp$
C) $0.5\ amp$
D) $2\ amp$
Explanation
(c) $i = \frac{m}{Zt} = \frac{0.972}{0.00018 \times 3 \times 3600} = 0.5\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.