Q. In the circuit shown, the currents $i_{1}\ and\ i_{2}$are
A) $i_{1} = 3A,i_{2} = 1A$
B) $i_{1} = 1A,i_{2} = 3A$
C) $i_{1} = 0.5A,\ i_{2} = 1.5\ A$
D) $i_{1} = 1.5\ A,\ i_{2} = 0.5\ A$
Explanation
(c) $R = \frac{12 \times 4}{12 + 4} + 2 = 5\Omega$
$I = \frac{E}{R + r} = \frac{12}{6} = 2A$
$I_{1} + I_{1} = 2A\ $
$I \propto \frac{1}{R}$
$\therefore I_{1} = 0.5A,\ I_{2} = 1.5A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.