Q. The emf is thermocouple changes sign at 600 K. If the neutral temperature is 210$℃$, the temperature of cold junction is
A) 180 K
B) 117 K
C) 93$℃$
D) 90$℃$
Explanation
(c) $\theta_{0} = 2\theta_{n} - \theta_{i} = 2 \times 210 - (600 - 273)$
= $420 - 327 = 93℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.