(d) $S = \left( \frac{100 - l}{l} \right).R$ Initially, $30 = \left( \frac{100 - l}{l} \right) \times 10 \Rightarrow l = 25cm$ Finally, $10 = \left( \frac{100 - l}{l} \right) \times 30 \Rightarrow l = 75cm$ So, shift $= 50cm$
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