(a) Given problem is the case of mixed grouping of cells
So total current produced $i = \frac{nE}{R + \frac{nr}{m}}$
Here $m = 100,\ n = 5000,\ R = 500\Omega$
$E = 0.15\ V$ and $r = 0.25\Omega$
$\Rightarrow i = \frac{5000 \times 0.15}{500 + \frac{5000 \times 0.25}{100}} = \frac{750}{512.5} \approx 1.5\ A$