(c) Potential gradient $x = \frac{e}{(R + R_{h} + r)}.\frac{R}{L}$ $\Rightarrow \frac{10^{- 3}}{10^{- 2}} = \frac{2}{(3 + R_{h} + 0)} \times \frac{3}{1} \Rightarrow R_{h} = 57\Omega$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.