Q. In the circuit, the potential difference across $PQ$ will be nearest to
A) $9.6\ V$
B) $6.6\ V$
C) $4.8\ V$
D) $3.2\ V$
Explanation
(d) Potential difference across $PQ\ i.e$. p.d. across the resistance of $20\Omega$ is $V = i \times 20$
and $i = \frac{48}{(100 + 100 + 80 + 20)} = 0.16A$
$\therefore V = 0.16 \times 20 = 3.2V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.