Q. In the given figure, potential difference between $A$ and $B$ is
A) 0
B) $5\ volt$
C) $10\ volt$
D) $15\ volt$
Explanation
(c) Equivalent resistance $R = 10 + \frac{10}{2} = 15\ k\Omega$
Current $i = \frac{30}{15} = 2 \times 10^{- 3}A$
Hence, potential difference between $A$ and $B$
$V = \left( \frac{2 \times 10^{- 3}}{2} \right) \times 10 \times 10^{3} = 10\ Volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.