Q. A steady current of $5\ amps$ is maintained for $45\ mins.$ During this time it deposits $4.572\ gm$ of zinc at the cathode of a voltmeter. E.C.E. of zinc is
A) $3.387 \times 10^{- 4}gm/C$
B) $3.387 \times 10^{- 4}C/gm$
C) $3.384 \times 10^{- 3}gm/C$
D) $3.394 \times 10^{- 3}C/gm$
Explanation
(a) $m = Zit \Rightarrow Z = \frac{m}{it} = \frac{4.572}{5 \times 45 \times 60} = 3.387 \times 10^{- 4}gm/C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.