One junction of thermocouple is at 0$℃$ and the other is at $T℃$. The thermo emf (in volts) is given by $\ E = 20 imes 10^{- 6}T - 0.02 imes 10^{- 6}T^{2}$ The maximum value of $E$ is

Question

One junction of thermocouple is at 0$℃$ and the other is at $T℃$. The thermo emf (in volts) is given by $\ E = 20 	imes 10^{- 6}T - 0.02 	imes 10^{- 6}T^{2}$ The maximum value of $E$ is

Dr. Abubacker · Accepted Answer

(a) For $E$ to be maximum
$\ \frac{dE}{dT} = 20 	imes 10^{- 6} - 0.02 	imes 10^{- 6} 	imes 2T = 0$
$\Rightarrow {\ T}_{n} = 500℃$
$	herefore E_{\max} = 20 	imes 10^{- 6}(500) - 0.02 	imes 10^{- 6}(500)^{2} =$5 mV

Q. One junction of thermocouple is at 0$℃$ and the other is at $T℃$. The thermo emf (in volts) is given by $\ E = 20 \times 10^{- 6}T - 0.02 \times 10^{- 6}T^{2}$ The maximum value of $E$ is

Explanation

Reviewed by Dr. Abubacker

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