(a) $\ \ \ \ \ \ \ \ \ P = \frac{V^{2}}{R}$ $\therefore R_{hot} = \frac{V^{2}}{P}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{200 \times 200}{1000} = 400\ \Omega$ $R_{cold} = \frac{400}{10} = 40\ \Omega$
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Ph.D. in Physics with 19+ years of teaching experience.