(b) Charge $Q = I\ t = 1.6\ \times 60 = 96\ C$ Let $n$ be the number of $Cu^{+ 2}\ $ions, then $ne = Q \Rightarrow n = \frac{Q}{e} = \frac{96}{2 \times 1.6 \times 10^{- 19}} = 3 \times 10^{20}$
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