Q. The equivalent resistance between the terminals $A\ and\ B$ in the following circuit is
A) 10$\ \Omega$
B) 20$\ \Omega$
C) 5$\ \Omega$
D) 30$\ \Omega$
Explanation
(b) 10$\Omega$ in series with 10$\Omega$ will gives
(10+10)=20$\Omega$
and 10$\Omega$ in series with 10$\Omega$ will gives
(10+10)=20$\Omega$
20$\Omega$ in parallel with 20$\Omega$ will gives
$\left( \frac{20 \times 20}{20 + 20} \right) = \frac{400}{40} = 10\Omega$
Resistance in series between points A and D
=5+10+5
=20$\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.