Q. An ammeter of $5\ ohm$ resistance can read $5\ mA.$ If it is to be used to read $100\ volt,$ how much resistance is to be connected in series
A) $19.9995\ \Omega$
B) $199.995\ \Omega$
C) $1999.95\ \Omega$
D) $19995\ \Omega$
Explanation
(d) By using $R = \frac{V}{i_{g}} - G \Rightarrow R = \frac{100}{5 \times 10^{- 3}} - 5 = 19,995\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.