Q. In the circuit shown in the figure, the current flowing in $2\ \Omega$ resistance

A) $1.4\ A$
B) $1.2\ A$
C) $0.4\ A$
D) $1.0\ A$
Explanation

(d) Since it’s a balanced Wheatstone bridge, the circuit can be redrawn as
[image:3_image174.emf]
$12I = 30(1.4\ I)$
$12I = 42 - 30I$
$\therefore I = 1\ A$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.