Q. In the circuit shown the cells $A$ and $B$ have negligible resistance. For $V_{A} = 12V,\ R_{1} = 500\Omega$ and $R = 100\Omega$ the galvanometer (G) shows no deflection. The value of $V_{B}$ is

A) $4V$
B) $2V$
C) $12V$
D) $6V$
Explanation

(b) [image:3_image175.emf]
Since deflection in galvanometer is zero so current will flow as shown in the above diagram
Current $I = \frac{V_{A}}{R_{1} + R} = \frac{12}{500 + 100} = \frac{12}{600}$
So $V_{B} = IR$
$= \frac{12}{600} \times 100 = 2V$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.