Equal potentials are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ration $r$ (iron)/$r$ (copper) of their radii must be (Given that specific resistance of iron = $1.0 imes 10^{- 7}\ ohm - m$ and specific resistance of copper = $1.7 imes 10^{- 8}ohm - m$)

Question

Equal potentials are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ration $r$ (iron)/$r$ (copper) of their radii must be (Given that specific resistance of iron = $1.0 	imes 10^{- 7}\ ohm - m$ and specific resistance of copper = $1.7 	imes 10^{- 8}ohm - m$)

Dr. Abubacker · Accepted Answer

(b) $\frac{r_{iron}}{r_{Copper}} = \sqrt{\frac{ho_{iron}}{ho_{copper}}} = \sqrt{\frac{1 	imes 10^{- 7}}{1.7 	imes 10^{- 8}}} = 2.4$

Explanation

Reviewed by Dr. Abubacker

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