Q. A certain current passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to 1 division. The galvanometer resistance is
A) 100$\ \Omega$
B) 99$\ \Omega$
C) 10$\ \Omega$
D) 9.9$\ \Omega$
Explanation
(b) Shunt is connected to the galvanometer
$i_{g} = \frac{iS}{S + G}$
$1 = \frac{100 \times 1}{(1 + G)}$
$\Longrightarrow \ \ G = 99\Omega\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.