Q. The current I drawn from the 5 V source will be
A) 0.33A
B) 0.5A
C) 0.67A
D) 0.17A
Explanation
(b) The given circuit can be redrawn as
[image:3_image177.jpeg]
Which is a balanced Wheatstone’s bridge and hence, no current flows in the centre resistor, so equivalent circuit would be as shown below.
So, $I = \frac{V}{R} = \frac{5}{10} = 0.5A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.