Q. The potential gradient along the length of a uniform wire is $10\ volt/metre.$ $B$ and $C$ are the two points at $30\ cm$ and $60\ cm$ point on a meter scale fitted along the wire. The potential difference between $B$ and $C$ will be
A) $3\ volt$
B) $0.4\ volt$
C) $7\ volt$
D) $4\ volt$
Explanation
(a) Potential gradient = Change in voltage per unit length
$\therefore 10 = \frac{V_{2} - V_{1}}{30/100} \Rightarrow V_{2} - V_{1} = 3\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.