Q. If the cold junction of a thermocouple is kept at $0℃$ and the hot junction is kept at $T℃,$ then the relation between neutral temperature $\left( T_{n} \right)$ and temperature of inversion $\left( T_{i} \right)$ is
A) $T_{n} = \frac{T_{i}}{2}$
B) $T_{n} = 2T_{i}$
C) $T_{n} = T_{i} - T$
D) $T_{n} = T_{i} + \ T$
Explanation
(a) It is found that temperature of inversion $\left( T_{i} \right)$ is as much above the neutral temperature $\left( T_{n} \right)$ as neutral temperature is above the temperature of the cold junction $(T),\ ie,$
$T_{i} - T_{n} = T_{n} - T\ or\ T_{i} = 2T_{n} - T$
But, here the cold junction is kept at $0℃,$ hence $T = 0.$
Thus, $T_{i} = 2T_{n}\ or\ T_{n} = \frac{T_{i}}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.