Q. In the electric circuit shown each cell has an emf of 2V and internal resistance of 1$\Omega$. The external resistance is 2$\Omega$. The value of the current I is(in ampere)
A) 2
B) 1.25
C) 0.4
D) 1.2
Explanation
(d) $Current = \frac{net\ emf}{net\ resistance\ }$
or $I = \frac{2 + 2 + 2}{1 + 1 + 1 + 2} = \frac{6}{5} = 1.2A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.